9+q/q^2=2

Solution for 9+q/q^2=2 equation:

9+q/q^2=2

We move all terms to the left:

9+q/q^2-(2)=0


Domain of the equation: q^2!=0

q^2!=0/

q^2!=√0

q!=0

q∈R


We add all the numbers together, and all the variables

q/q^2+7=0

We multiply all the terms by the denominator


q+7*q^2=0

We add all the numbers together, and all the variables

7q^2+q=0

a = 7; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·7·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*7}=\frac{-2}{14}
=-1/7
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*7}=\frac{0}{14}
=0
$